Calculus 1 relative rates question

Click For Summary
SUMMARY

The discussion focuses on calculating the rates of change of the angle of elevation θ for an airplane flying at an altitude of 8 miles towards an observer, with a speed of 600 miles per hour. The relevant equations involve the relationship between the angle of elevation and the horizontal distance x, expressed as tan(θ) = 8/x. The solution requires the application of implicit differentiation, leading to the equation sec²(θ) * dθ/dt = (8/x²) * 600. The final step involves evaluating dθ/dt at θ = 30°, 60°, and 80°, ensuring angles are converted to radians.

PREREQUISITES
  • Understanding of calculus concepts, specifically implicit differentiation.
  • Familiarity with trigonometric functions, particularly tangent and secant.
  • Knowledge of rates of change in relation to motion problems.
  • Ability to convert angles from degrees to radians.
NEXT STEPS
  • Practice implicit differentiation with various trigonometric functions.
  • Learn how to apply related rates in real-world motion problems.
  • Study the conversion between degrees and radians in trigonometric contexts.
  • Explore the application of secant and tangent functions in calculus problems.
USEFUL FOR

Students studying calculus, particularly those tackling related rates problems, as well as educators looking for examples of real-world applications of trigonometry and differentiation.

ivanhu1
Messages
1
Reaction score
0

Homework Statement



An airplane flies at an altitude of 8 miles toward a point directly over an observer (see figure). The speed of the plane is 600 miles per hour. Find the rates at which the angle of elevation θ is changing when the angle is θ = 30°, θ = 60°, and θ = 80°.


The Attempt at a Solution



I tried solving this problem by my self but i kept getting stuck at one the same spot every time.


(db/dt)=600
y=8

tanθ=8/x

sec^2(θ) * dθ/dt = 8/x^2 * 600

and that's as far i get every time and i don't know if I'm doing it right or not.
 
Physics news on Phys.org
ivanhu1 said:

Homework Statement



An airplane flies at an altitude of 8 miles toward a point directly over an observer (see figure). The speed of the plane is 600 miles per hour. Find the rates at which the angle of elevation θ is changing when the angle is θ = 30°, θ = 60°, and θ = 80°.


The Attempt at a Solution



I tried solving this problem by my self but i kept getting stuck at one the same spot every time.


(db/dt)=600
Makes more sense to call the plane's velocity dx/dt. Also, since the plane is flying toward the observer, x is decreasing, so dx/dt < 0.
ivanhu1 said:
y=8

tanθ=8/x

sec^2(θ) * dθ/dt = 8/x^2 * 600
d/dt(8/x) = d/dt(8x-1) = -8x-2 * dx/dt
Notice that the right side represents a positive number if x > 0.

Other than that, your equation of the rates looks fine. Now solve for dθ/dt, and evaluate it at the three given values of θ. Don't forget to convert the angles to radians.
ivanhu1 said:
and that's as far i get every time and i don't know if I'm doing it right or not.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
11K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 11 ·
Replies
11
Views
8K
  • · Replies 3 ·
Replies
3
Views
7K
Replies
8
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K