Rate of Change: How Fast is the Length of a Shadow Decreasing?

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SUMMARY

The discussion focuses on calculating the rate at which the length of a man's shadow decreases as he walks towards a street lamp. The man, standing at 1.8 meters tall, walks at a speed of 10 m/s towards a lamp that is 7 meters high. The relationship between the man's position, the length of his shadow, and the height of the lamp is established using similar triangles, leading to the differentiation of the shadow length with respect to time. The key formula derived is based on the relationship between the shadow length and the man's distance from the lamp.

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jakealucard
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A man 1.8 m tall walks at speed of 10m/s towards a street lamp which is 7m above the ground. How fast is the length of the man's shadow decreasing?


My attempt:

Let the man's shadow and the lamp's length be l, and the distance be d and time be t. Given, dd/dt = 10.

I am supposed to find dl/dt.

dd/dt= dl/dt X dd/dl

So how do I find dd/dl?:confused:
 
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You can imagine the man walking on the x-axis towards the y-axis. Call his position x and the length of his shadow s.
The key to these types of problems is using similar triangles. So we can get a relation between s and x.

(1.8/s) = (7/x+s)

Get s on one side and differentiate with respect to t. And remember dx/dt = -10 since x is decreasing.

I hope i didn't make any mistake. Check the book to make sure if you have the answer.
 
Draw a picture and think "similar triangles".
 

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