Rate of change of radius through a a circular wire loop?

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SUMMARY

The discussion focuses on calculating the rate of change of the radius of a circular wire loop required to maintain zero induced electromotive force (emf) as the magnetic field decreases. Given a radius of 19 cm and a magnetic field strength of 0.690 T decreasing at a rate of -1.0×10^-2 T/s, the area change rate was determined to be 0.0016 m²/s. Consequently, the required rate of radius increase, dr/dt, was calculated to be 22.8 mm/s.

PREREQUISITES
  • Understanding of Faraday's Law of Electromagnetic Induction
  • Familiarity with the formula for magnetic flux: Flux = BAcos(theta)
  • Knowledge of the relationship between area and radius for a circle: Area = πr²
  • Ability to differentiate area with respect to time: dA/dt = 2πr(dr/dt)
NEXT STEPS
  • Study Faraday's Law in detail to understand induced emf calculations
  • Learn about the implications of changing magnetic fields on loop geometry
  • Explore practical applications of electromagnetic induction in engineering
  • Investigate the effects of varying radius on induced emf in different configurations
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Physics students, electrical engineers, and anyone interested in electromagnetic theory and its applications in circuit design and analysis.

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A circular wire loop of radius r = 19 cm is immersed in a uniform magnetic field B = 0.690 T with its plane normal to the direction of the field. If the field magnitude then decreases at a constant rate of −1.0×10^-2 T/s, at what rate should r increase so that the induced emf within the loop is zero?



Flux=BAcos(theta)
emf=dq/dt


I tried this and I got an equation of 0=(Bcos0)(dA/dt)+(Acos0)(dB/dt)
and I plugged it into get dA/dt=.0016m^2/s and then i solved for the radius in this case which is .0228m and my answer is supposed to be in mm/s so i got 22.8 mm/s as my answer.
 
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Area = πr^2.
hence dA/dt = 2πr*dr/dt.
Now find dr/dt.
 

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