- #1

- 92

- 1

thanks

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- Thread starter ronaldor9
- Start date

- #1

- 92

- 1

thanks

- #2

- 42

- 0

[tex]V_p=\frac{\pi}{6}d^3=\frac{\pi}{6}(0.5\times 10^{-3})=6.5\times 10^{-11}\text{m}^3[/tex]

The volume of a grain of sand is given by:

[tex]V_s=\frac{V_p}{10000}=\frac{6.5\times 10^{-11}}{10000}=6.5\times 10^{-15}\text{m}^3[/tex]

The diameter of a grain of sand is given by:

[tex]d_s=\sqrt[3]{\frac{6V_s}{\pi}}=2.3\times 10^{-5}\text{m}[/tex]

- #3

- 92

- 1

yeah thats what ive been geting, the book is wrong it had it as 0.025 mm!

- #4

- 42

- 0

They are the same order of magnitude, the difference could just be due to rounding errors

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