Solving the Poppy Seed and Sand Diameter Puzzle

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The discussion centers on calculating the diameter of grains of sand contained within a spherical poppy seed, which has a diameter of 0.5 mm. The volume of the poppy seed is calculated to be approximately 6.5 x 10^-11 m³, leading to a volume per grain of sand of 6.5 x 10^-15 m³. Using this volume, the diameter of each grain of sand is determined to be about 2.3 x 10^-5 m, or 0.023 mm. The original book's stated diameter of 0.025 mm is deemed incorrect, with the discrepancy attributed to potential rounding errors. This highlights the importance of precise calculations in volume and diameter estimations.
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Suppose a poppy seed is .5 mm in diameter and holds ten thousand grains of sand. Find the diameter of each grain of sand? I am reading this book and the stated answer seems wrong.
thanks
 
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Assuming the poppy seed to be spherical, its volume is given by:

V_p=\frac{\pi}{6}d^3=\frac{\pi}{6}(0.5\times 10^{-3})=6.5\times 10^{-11}\text{m}^3

The volume of a grain of sand is given by:

V_s=\frac{V_p}{10000}=\frac{6.5\times 10^{-11}}{10000}=6.5\times 10^{-15}\text{m}^3

The diameter of a grain of sand is given by:

d_s=\sqrt[3]{\frac{6V_s}{\pi}}=2.3\times 10^{-5}\text{m}
 
yeah that's what I've been geting, the book is wrong it had it as 0.025 mm!
 
They are the same order of magnitude, the difference could just be due to rounding errors
 
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