RC Circuit and finding Maximum Voltage

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The discussion revolves around solving an RC circuit problem involving a 200 V battery, resistors R1 and R2, and a capacitor. The initial current through the battery after closing the switch is calculated to be approximately 0.176 A, while the steady-state current is about 0.117 A. The main challenge is determining the maximum voltage across the capacitor, which is equal to the voltage across resistor R2 in steady state, as no current flows through the capacitor in this condition. The voltage across R2 can be found using Ohm's law, relating it to the steady-state current. Understanding that the capacitor blocks DC current is crucial for solving part c of the problem.
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Homework Statement



Use the value:
E = 200 V,
Horizontal resistor R1 = 1136 capital omega,
Vertical resistor R2 = 568 capital omega, and
Capacitor C = 5.37 mu or micro F,

t25p116.gif


(a) the initial current through the battery just after the switch is closed:
(b) the steady state current through the battery when the switch has been closed for a long time:
(c) the maximum voltage across the capacitor:


Homework Equations



R = V/I
C = Q/V

The Attempt at a Solution



I found a and b to be as follows (using loops)

a) 0.176056 A
b) 0.117371 A

I'm having trouble with part c)...I don't know how to relate the current i found in part a) or b) to the definition of capacitance to find the maximum voltage. Could anyone help or point me in the right direction? thanks!
 
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Your a and b look good to me. The capacitor will be charged so the voltage across it is equal to the voltage across R2. No current will flow through the capacitor (it blocks DC), so the voltage on R2 is the same as if their was no capacitor there.
 
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