Reaction of alkyl halides with strong unhindered bases

[alingy1]

Please look at the image. For (b) and (c), what the solution manual says makes no sense to me.
You're reacting a primary alkyl halide with an unhindered base EtONa. They say that the only product is the alkene. Why do they not consider the S_N2 reaction that WILL take place in larger quantity?
I'm uploading the question too.

 

[Teemo]

There is no other S_N2 reaction. There aren't any other leaving groups.

 

[MrNano]

I am actually not too sure, but I think it is due to the steric hinderance. The hinderance does not always have to be on the beta carbon, if you compare the structure to a neopentylic structure, which can never participate in an Sn2, there are similarities, except that there are only two metyl substituents, instead of three.

In all honesty, if I would not have known the answer i would have gone for Sn2 as well so I would also love to see a good explanation.