Real analysis: show that a continuous function is defined for irrationals

In summary, we are given a continuous function f defined on (a, b) such that f(x)=0 for all rational numbers x in (a, b). To prove that f(x)=0 on (a, b), we use proof by contradiction and the fact that f is continuous and that rational numbers are dense in the real numbers.
  • #1
nps12345
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Let f be a continuous function defined on (a, b). Supposed f(x)=0 for all rational numbers x in (a, b). Prove that f(x)=0 on (a, b).

i don't even know where to start...any tips just to point me in the right direction?
 
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  • #2
There's a couple of ways you can approach this problem. Did you try proof by contradiction?

Let f be a continuous function defined on (a, b). Assume f(x)=0 for all rational numbers x in (a, b) and assume that f(x)≠0 on (a, b), so...
 
  • #3
You'll need two things for this problem:

1) If f is continuous and if [itex]x_n\rightarrow x[/itex], then [itex]f(x_n)\rightarrow f(x)[/itex].

2) For every real number x there exists a sequence of rational numbers that converges to x. This is saying that [itex]\mathbb{Q}[/itex] is dense in [itex]\mathbb{R}[/itex]

Try to do something with these things...
 

1. What is the definition of a continuous function?

A continuous function is a function that has no sudden or abrupt changes in its graph. In other words, the function is defined for all points within its domain, and the limit of the function as the input approaches a certain value equals the value of the function at that point.

2. How do you prove that a function is continuous?

To prove that a function is continuous, we must show that it satisfies the three conditions of continuity: 1) the function is defined at the point in question, 2) the limit of the function at that point exists, and 3) the limit equals the value of the function at that point.

3. Why is it important for a continuous function to be defined for irrationals?

A continuous function being defined for irrationals is important because it ensures that the function is well-defined and has no gaps or holes in its graph. This allows us to accurately analyze and make conclusions about the behavior of the function.

4. Can a function be continuous for irrationals but not for rationals?

Yes, it is possible for a function to be continuous for irrationals but not for rationals. This is because the definition of continuity for a function only requires it to be defined and have a limit at a point, and this can be satisfied for irrationals but not for rationals.

5. How does the density of irrationals in the real numbers relate to the continuity of a function?

The density of irrationals in the real numbers means that between any two rational numbers on the real number line, there exists an irrational number. This property is important for the continuity of a function because it ensures that the function is defined and has a limit at every point within its domain, including irrational numbers.

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