MHB Real Estate math word problem help

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The discussion revolves around solving a real estate math problem related to property valuation based on zoning classifications. The user seeks assistance in determining the correct formulas for calculating the per square foot value of a mixed-use undeveloped property. The calculations reveal that one acre of commercial land costs $13,068, while multi-unit and single-unit residential lands cost $5,227.20 and $2,613.60, respectively. The final answer for the property value is confirmed to be $1.62 per square foot. The user expresses a desire to memorize the solution process and improve their understanding of similar problems.
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I am studying to take a real estate exam. I am having problems determining the correct formula on the percentage problems. I need help solving the answer and understanding the correct formula. Help is much appreciated. The math problem is:
The subject is a mixed use undeveloped property with 3 acres zoned commercial,
5 acres zoned multi-unit, and 2 acres zoned single-unit. A similar 10-acre property
recently sold for $1.80 per sf with 4 acres zoned commercial, 4 acres zoned multiunit,
and 2 acres zoned single-unit residential.

Based on this one sale property, what is the per square foot value of the subject
property if multi-unit land typically sells for 40% of commercial land prices, and
single-unit residential land sells for 20% of commercial land prices?
 
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Let C be the cost of one acre of "commercial land". Since "multi-unit land typically sells for 40% of commercial land prices" one acre of "multi-unit land" cost .4C. Since "single-unit residential land sells for 20% of commercial land prices" one acre of single-unit residential land" cost .2C.

"A similar 10-acre property recently sold for 1.80 per sf with 4 acres zoned commercial, 4 acres zoned multi-unit, and 2 acres zoned single-unit residential."

There are 43560 square feet per acre so 1.80 per sf is (1.80)(43560)= 78408 per acre.

So 4C+ 4(.4C)+ 2(.2C)= 4C+ 1.6C+ .4C= 6C= 78408. C= 78408/6= 13068 . One acre zoned commercial costs 13068, one acre zoned multi-unit cost .4(13068)= 5227.20, and one acre zoned single unit residential costs .2(13068)= 2613.60.

The question asks for the cost of 3 acres zoned commercial, 5 acres zoned multi-unit, and 2 acres zoned single-unit.

That is 3(13068)+ 5(5227.20)+ 2(2613.60).
 
Thank you Country Boy.

Great job, the answer of $1.62 per sf is correct. Now I will need to figure out how to memorize the way to solve this type of question. There are a few other practice questions I have. I will reverse engineer this equation, and hopefully after a few go through I will have it down. Your help is much appreciated.

Country Boy said:
Let C be the cost of one acre of "commercial land". Since "multi-unit land typically sells for 40% of commercial land prices" one acre of "multi-unit land" cost .4C. Since "single-unit residential land sells for 20% of commercial land prices" one acre of single-unit residential land" cost .2C.

"A similar 10-acre property recently sold for 1.80 per sf with 4 acres zoned commercial, 4 acres zoned multi-unit, and 2 acres zoned single-unit residential."

There are 43560 square feet per acre so 1.80 per sf is (1.80)(43560)= 78408 per acre.

So 4C+ 4(.4C)+ 2(.2C)= 4C+ 1.6C+ .4C= 6C= 78408. C= 78408/6= 13068 . One acre zoned commercial costs 13068, one acre zoned multi-unit cost .4(13068)= 5227.20, and one acre zoned single unit residential costs .2(13068)= 2613.60.

The question asks for the cost of 3 acres zoned commercial, 5 acres zoned multi-unit, and 2 acres zoned single-unit.

That is 3(13068)+ 5(5227.20)+ 2(2613.60).
 
Is "memorizing" all you can do? I recommend learning the basic definitions, tthen thinking!
 
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