Really - Taylor Polynomial Approximation Error

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The discussion focuses on using Taylor's theorem to determine the error in approximating cos(0.3) with a Taylor polynomial. An upper bound for the error was calculated as Rn = (-sin(z)/5!) * (0.3)^5, yielding approximately 0.00002. To find the exact error, it is suggested to compute the actual value of cos(0.3) using a calculator and subtract the Taylor series approximation. This method confirms that the exact error is less than the calculated upper bound. The approach emphasizes the practical application of Taylor's theorem in estimating approximation accuracy.
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Homework Statement



Use Taylor's theorem to obtain an upper bound of the error of the approximation. Then calculate the exact value of the error.

cos(.3) is approximately equal to 1 - (.3)^2/2! + (.3)^4/4!

Homework Equations





The Attempt at a Solution



I came up with upper bound saying

Rn = (-sinz/5!)*(.3)^5 < (.3)^5/5!

so the upper bound is (.3)^5/5! which is about .00002

But for the exact error I have no idea how to calculate it. There aren't any examples in my textbook.
 
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I think they want you to use a calculator to actually find cos(.3) then subtract the approximation to see if how well your estimate worked.
 
The only way to calculate the exact value of the error is to take the exact value of the cosine and subtract the value of the series. I think they just mean punch cos(.3) into your calculator and then subtract the series value and see that it's less than the remainder term.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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