Rearranging Equation for Thermodynamics Question

[AbbeyC172]

Homework Statement

I am trying to figure out how to get the V2^2 alone and I feel that this is very basic rearranging of equations but I have been stuck on it forever now. Thank you so much in advance.


-75 kj/s= 4.09 kg/s (-190.3 + (V2)^2 - (60 m/s)^2 / 2)
[/B]

Homework Equations

Trying to solve for V2^2 the exit velocity of steam using:


Q loss = m(h2-h1+ V2^2-V1^2 / 2)[/B]


Is there a better way to write this fraction out? I do not see fraction capability in the insert symbols option.

The Attempt at a Solution

I have subtracted -75 kj/s from both sides and then get stuck on how to get that V2^2 to the left side. [/B]

 

[kuruman]

First remove the parentheses by multiplying everything inside them by $m$. Then move everything that does not have V₂ to the other side and change signs at the same time. Finally multliply and divide by what's needed to isolate V₂.

 

[gneill]

Q loss = m(h2-h1+ V2^2-V1^2 / 2)Is there a better way to write this fraction out? I do not see fraction capability in the insert symbols option.

You can use LaTeX syntax to render the mathematics more "professionally" as it might appear in a book. See the LaTeX link at the bottom left of the edit window.

In your formula above, is it only the V1^2 term that is divided by two, or is it supposed to be (V2^2 - V1^2)/2 ?

 

[AbbeyC172]

You can use LaTeX syntax to render the mathematics more "professionally" as it might appear in a book. See the LaTeX link at the bottom left of the edit window.

In your formula above, is it only the V1^2 term that is divided by two, or is it supposed to be (V2^2 - V1^2)/2 ?

It is the latter, (V2^2 - V1^2)/2