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## Homework Statement

Steam, at 15 bar and 280oC, enters a nozzle with an initial velocity of 125 m/s. The steam enthalpy at the exit section is 2800 kJ/kg and the heat loss is 25 kJ/kg. What is the exit steam velocity?.

## Homework Equations

1)Qin - Qout = m [h2-h1+((c2

^{2}-c1

^{2}))/2]

2)h = Pv + u

3)A1c1/ρ1 = A2c2/ρ2

## The Attempt at a Solution

0-25k = m((2800-h1)+-125^2/2)

Steam is not an ideal gas so I can't use Pv=mRT. I have two unknowns and I don't know where to start. I hope you can help.