Steam, at 15 bar and 280oC, enters a nozzle with an initial velocity of 125 m/s. The steam enthalpy at the exit section is 2800 kJ/kg and the heat loss is 25 kJ/kg. What is the exit steam velocity?.
1)Qin - Qout = m [h2-h1+((c22-c12))/2]
2)h = Pv + u
3)A1c1/ρ1 = A2c2/ρ2
The Attempt at a Solution
0-25k = m((2800-h1)+-125^2/2)
Steam is not an ideal gas so I can't use Pv=mRT. I have two unknowns and I don't know where to start. I hope you can help.