Recoil velocity of atom interms of mass and energy

AI Thread Summary
The discussion revolves around calculating the recoil velocity of an atom after it absorbs a photon, focusing on the relationship between energy, mass, and momentum. Participants emphasize the importance of using conservation of momentum, noting that the momentum of the photon is related to its energy, while the atom's recoil energy is expressed in terms of its mass and velocity. There is confusion regarding the correct application of formulas, particularly in distinguishing between the momentum of the photon and the atom. Some contributors mention difficulties in relating the equations and express frustration over discrepancies with textbook answers. The conversation highlights the complexities of energy conservation in atomic interactions, especially when considering photon absorption and electron transitions.
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Homework Statement


I have a question to answer but am struggling to even start it. The question is basically an atom absorbs a photon (energy E), rest mass of atom is m, find recoil velocity in terms of E and m after absorbtion.


Homework Equations


i think i need th emomentum of the photon which i believe is p = m(rel) * c and rest mass of atom m = E/c^2 but that is as far as i get.


The Attempt at a Solution


S
Please see relevant equations above
 
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Hi,
I will tell you in small steps, so you can get the solution.
1)First find recoil energy (ER). It is just kinetic energy (KE). Use mass m and velocity v.
2)Now relate the equation in (1) to atom's momentum pa. a for atom.
3)What is the momentum of photon pp (subscript p for photon) with energy E (remember photon travels with speed of light c)?
4)Apply conservation of momentum, i.e. pp=pa.
5)When you apply and solve for ER you get ER in terms of energy E, m and c.
good luck.
 
Hi Rajini, I have tried to follow your simple steps but unfortunately am still baffled, I find it dificult to get my head around this type of problem!. What I have is
1) Er = 1/2mv^2
2) Pa = (M(atom) + M(photon))v(atom) - now not sure how to relate this with 1
3) Pp = gammaM(photon)V(photon)

Unfortunately that is it at the moment, my mind is blank!

I will keep plugging away but thanks for your help anyway.
 
Hi,
I have given you more details.
You can related step 2 to 1.
What is the formula for momentum ? and formula for momentum of photon ?
TIP: find momentum for atom and photon separately (dont add)
also 3. is wrong (photon has no mass) !
Please write what all you did?
 
Last edited:
Hello, I am stuck on the same problem! But the answer given above does not work. Momentum is conserved, but mechanical energy is *not*, because the atom absorbs the energy and an electron jumps to a higher orbit in response. I assumed the Doppler effect for light was involved, and I got exactly double the result the book did (Bransden and Joachain, Chapter 1, problem 21.) I can't find the factor of two anywhere. I used an expansion of the square root and approximated.
 
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