Reduce angular momentum from Iw to mvr

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The discussion centers on the relationship between angular momentum and its reduction for a point particle. The equation L=Iω is analyzed, where I=Mr² and ω=rxv, leading to L=Mr²(rxv) which simplifies to L=r²(rxp). The contributor encounters an issue with an extra factor of r², suggesting that this reduction only holds true when r=1, which is deemed impractical. A suggestion is made that a missing factor of 1/|r|² could resolve the discrepancy. The conversation highlights the complexities in deriving angular momentum for point particles in vector form.
Aziza
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In vector form,

L=Iω.

I am trying to show that for a point particle, this reduces to L=rxp, but am getting an extra factor of r2 :

For the case of a point particle, I=Mr2.
Also, ω=rxv.
Plugging these into L=Iω gives:

L=Mr2(rxv) = r2(rxp).

Thus this reduces to a point particle only for r=1..but that is silly.

I appreciate any help!:)
 
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