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Reduce the boolean expression to two literals

  1. Jan 31, 2013 #1
    1. The problem statement, all variables and given/known data

    ABC'D + A'BD + ABCD

    3. The attempt at a solution

    Here is as far as I have gotten:

    BD (AC' + A' + AC)
    BD (AC' + A')

    According to Wolfram Alpha, the answer should just be BD. Can someone help me get there?
     
    Last edited: Jan 31, 2013
  2. jcsd
  3. Jan 31, 2013 #2

    Filip Larsen

    User Avatar
    Gold Member

    Given the problem statement is correct you have two errors in the first line (a missing negation and a case of swapped symbol). I recommend you start from the beginning and take each step slowly, making sure all the symbols are transformed correctly along the way.
     
  4. Jan 31, 2013 #3
    I fixed the errors, sorry. Can someone tell me where to go next?
     
  5. Jan 31, 2013 #4
    Never mind, just solved it!

    Last steps:

    BD (A(C+C') + A')
    BD (A+A')
    BD
     
  6. Jan 31, 2013 #5
    Are you familiar with A+BC=(A+B)(A+C)?

    EDIT: Nvm, this isn't going to help.
     
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