Reduce the volume of aluminumm by 10%

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Homework Help Overview

The problem involves determining the ocean depth at which the volume of an aluminum sphere would be reduced by 0.10%. The context includes concepts related to pressure and material properties, specifically the bulk modulus of aluminum.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between pressure and volume reduction, with one noting the need for the bulk modulus of aluminum. There are questions about the calculations involving pressure, density, and the resulting depth.

Discussion Status

Some participants have provided guidance on finding the bulk modulus and suggested using the density of seawater instead of freshwater. There is an ongoing exploration of the calculations, with one participant expressing uncertainty about their results compared to expected values.

Contextual Notes

Participants are navigating the specifics of material properties and the implications of using different densities in their calculations. There is a noted confusion regarding the volume reduction percentage initially stated.

iceman_ch
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Homework Statement



At what ocean depth would the volume of an aluminum sphere be reduced by 0.10%?

Homework Equations



P=pgh

The Attempt at a Solution



I know how to get pressure at different depths. But what I don't know is how much pressure it takes to reduce the volume of aluminum. I can't find a table for it anywhere.
 
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That is a little hard to find. The number you are after is actually called a bulk modulus for aluminum. Try searching for that.
 
BTW, I'm also glad you aren't really trying to reduce it by 10%. Only 0.10%. Whew.
 
thank you for pointing that out. I actually thought it was 10%. This whole I was thinking wow that has to be really deap.
 
I found the bulk modulus in 2 places. I found it at wikipedia and the book. I used the books which was 7x10^10. The books density for water is 1000. So when I take the modulus and multiply it be .001 then I take that answer and divide it by 1000 for the density and then by 9.8 for acceleration. That shoul leave me with height. It is was 7.142 Km. This answer is incorrect. To me it seems right but the homwork says it is 6.98. Why was my first answer wrong?
 
have you tried using density of sea water? thas should reduce the result by about 2.5 to 3 percent.
 
Last edited:
That must be what it is. I just used water.
 

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