Regarding r and sign convention for Position vectors for moments

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SUMMARY

The discussion centers on the understanding of position vectors and torque calculations in physics, specifically using the equation \(\vec \tau = \vec r \times \vec F\). The position vectors are defined as \(r_1 = -1.5j\) and \(r_2 = r_3 = 0\), indicating that the forces are applied at specific points relative to point A along the axis of rotation. The conversation highlights the importance of defining moments about an axis and clarifies that the moment about a fixed axis remains constant regardless of the point chosen on that axis.

PREREQUISITES
  • Understanding of vector notation and operations, particularly cross products.
  • Familiarity with torque and its calculation in physics.
  • Knowledge of fixed and variable axes in rotational dynamics.
  • Basic principles of mechanics related to forces and moments.
NEXT STEPS
  • Study the concept of torque in more detail, focusing on \(\vec \tau = \vec r \times \vec F\).
  • Learn about the conditions under which the moment of a force about an axis is zero.
  • Explore fixed versus variable axes in rotational motion and their implications.
  • Review examples of calculating moments about different points on an axis.
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Students studying physics, particularly those focusing on mechanics and rotational dynamics, as well as educators looking to clarify concepts related to torque and position vectors.

7Lions
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Homework Statement



34qqy3b.png




The Attempt at a Solution



I'm having trouble understanding how r1 = -1.5j and r2= r3 = 0.

Can anyone make this a little clearer for me? I've spent quite a while trying to wrap my head around it but to no avail.
 
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The torque with respect to a point A is \vec \tau = \vec r \times \vec F, where \vec r is the position of the point of application of the force with respect to A. A has to be along the axis of rotation. The vector r1 (red in the picture) points from A to the application point of the forces.
attachment.php?attachmentid=66707&d=1392656774.jpg

ehild
 

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Red in the picture? Did you post a picture soewhere? I'm unable to see it
 
Could it be that the picture in post 1 continues a bit more? r2 = r3 = 0 because those lines intersect AB at B and at A. At the lower edge I see a u##_{AB}## pop up and it might well continue with a calculation of the distance between r##_1## and u##_{AB}##
 
7lions: Do you have a definition for the moment of the force about an axis?
Do you know in what conditions this will be zero?
 
You have ##\vec \tau = \vec r \times \vec F## for the ##moment## about the axis prependicular to ##\vec r## and ##\vec F##. The axis "goes trhough" the origin of ##\vec r##.
 
Ah, I'm' "helping" nose, which is unnecessary, sorry. It looks as if the lions are asleep in the jungle tonight. I turn in too... :smile:
 
BvU said:
You have ##\vec \tau = \vec r \times \vec F## for the ##moment## about the axis prependicular to ##\vec r## and ##\vec F##. The axis "goes trhough" the origin of ##\vec r##.

Well, this is the torque (moment of the force) about a point.
The moment about a fixed axis is less frequently mentioned.
This is the reason I asked about it.

The definition I know is that you take any point on the axis and calculate the moment about that point. And then you find the component of the moment parallel to the axis. It turns out that no matter what point you choose on the axis, the parallel component is the same.
And this is the moment about the axis. The perpendicular component will try to rotate the axis. But as the axis is "fixed", this has no effect.

I just wanted to make sure that this is the definition the OP knows about.
 

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