Torque: Find Length of Moment Arm & Calculate Magnitude/Sign

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Homework Help Overview

The discussion revolves around calculating the moment arm and torque related to a force vector about a specific point. The subject area is torque in physics, focusing on the relationship between force, moment arm, and the resulting torque's magnitude and sign.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the definition of the moment arm and its role in calculating torque. Questions arise regarding the sign of the torque and the conventions used in determining it. Some participants express confusion about the relationship between the moment arm and torque.

Discussion Status

Participants are actively engaging in clarifying concepts related to torque and moment arms. Some guidance has been provided regarding the conventions for determining the sign of torque, and multiple interpretations of the moment arm are being explored.

Contextual Notes

There is an ongoing discussion about the conventions used for torque calculations, including the significance of clockwise versus counterclockwise directions. Some participants express uncertainty about the definitions and relationships involved, indicating a need for further clarification.

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Homework Statement


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a) What is the length, rmr_m, of the moment arm of the force F→F_vec about point p?

b) Find the torque τtau about p due to F→F_vec. Your answer should correctly express both the magnitude and sign of τ.

The Attempt at a Solution

a) I'm inclined to state the answer as -rsinΘ but apparently the answer is r sin Θ.
Is there a reason why the sign is positive?
 
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negation said:

Homework Statement


View attachment 68238

a) What is the length, rmr_m, of the moment arm of the force F→F_vec about point p?

b) Find the torque τtau about p due to F→F_vec. Your answer should correctly express both the magnitude and sign of τ.


The Attempt at a Solution




a) I'm inclined to state the answer as -rsinΘ but apparently the answer is r sin Θ.
Is there a reason why the sign is positive?
always use the magnitude ( positive number) of the force and position vectors and moment arm when calculating torques. The sign of the torque is then determined by clockwise or counterclockwise torque , ccw is plus in this example, cw is minus, simply by convention.
 
PhanthomJay said:
always use the magnitude ( positive number) of the force and position vectors and moment arm when calculating torques. The sign of the torque is then determined by clockwise or counterclockwise torque , ccw is plus in this example, cw is minus, simply by convention.

Understood.

What about (b)? I'm really quite unclear about what moment of arm is and how it relates to torque. Would you mind shedding some light? (I appreciate)
 
negation said:
Understood.

What about (b)? I'm really quite unclear about what moment of arm is and how it relates to torque. Would you mind shedding some light? (I appreciate)
There are several ways to calculate torque about a point. One such way is to use torque = magnitude of force times the perpendicular distance from the line of action of the force to point, where the perpendicular distance is called the 'moment arm'. Another is to use the cross product rule. Sign of torque is plus if ccw, minus if cw, using the convention that ccw torques are positive.
 
PhanthomJay said:
There are several ways to calculate torque about a point. One such way is to use torque = magnitude of force times the perpendicular distance from the line of action of the force to point, where the perpendicular distance is called the 'moment arm'. Another is to use the cross product rule. Sign of torque is plus if ccw, minus if cw, using the convention that ccw torques are positive.


And the dashed lines extending from F vector is the moment arm?
 
negation said:
And the dashed lines extending from F vector is the moment arm?
No, the moment arm is the perpendicular distance from the line of action of the force vector to the point, which woukld be rm on your sketch.
 

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