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Regarding with two port electrical network

  1. Oct 2, 2011 #1
    my problems comes from one of a book how to solve this one this is regarding with two port electrical network

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  2. jcsd
  3. Oct 2, 2011 #2
    For Z parameter

    [tex]\left(\begin{array}{c}V_1\\V_2\end{array}\right)\;=\;\left(\begin{array}{cc}Z_{11} & Z_{12}\\Z_{21} & Z_{22}\end{array}\right)\;\left(\begin{array}{c}I_1\\I_2\end{array}\right)[/tex]

    [tex] V_1=Z_{11}I_1+Z_{12}I_2[/tex]

    [tex] V_2=Z_{21}I_1+Z_{22}I_2[/tex]

    [tex]Z_{11}=\left(\frac{V_1}{I_1}\right)_{I_2=0}\;\;,\;\;Z_{12}=\left(\frac{V_1}{I_2}\right)_{I_1=0} \;\;,\;\;Z_{21}=\left(\frac{V_2}{I_1}\right)_{I_2=0}\;\;,\;\;Z_{22}=\left(\frac{V_2}{I_2}\right)_{I_1=0}[/tex]

    For I=0 means open circuit.

    For Y parameter just (I)=(Y)(V) and make one of the V=0 which is short circuit.

    For transformer it is reciprocal circuit so Z12=Z21 and Y12=Y21.

    I have not work out the detail, just use this on the transformer and it should work.
    Last edited: Oct 2, 2011
  4. Oct 2, 2011 #3
    thanks for your answer.but consider this
    the circuit is reciprocal so that[y][/21]=[y][/12] , Am I right?
  5. Oct 2, 2011 #4

    The Electrician

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