I was pondering a question today. If you have a cube with a sphere inside of it, and the sphere is growing at 2 m/s. The cube itself is expanding at 1 m/s. If the cube is 5 x 5 x 5, and the sphere has a radius of 2. Is it possible to calculate when the sphere and the cube will be expanding at the same rate? I also assumed that eventually the sphere will overcome the cube.(adsbygoogle = window.adsbygoogle || []).push({});

V=4/3*pi*r^2

dv=4/3*pi*2r dr/dt

V=x^3

dv=3x^2

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# Homework Help: Related rates and cube with a sphere inside of it

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