Related Rates Problem: 13m Ladder Leaning Against Wall

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A 13m ladder is leaning against a wall, with the top slipping down at a rate of 2m/s. The problem involves finding how fast the foot of the ladder moves away from the wall when the top is 5m from the ground. The solution uses the Pythagorean theorem to establish the relationship x^2 + y^2 = 13^2, followed by implicit differentiation to derive the equation. The calculated speed of the foot moving away from the wall is 5/6 m/s, which is confirmed as correct. An alternative method using a different formula for related rates was also mentioned.
raoulduke1
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Could someone verify my answer for this question?

13m ladder is leaning against a wall.
If the top of the ladder slips down the wall at a rate of 2m/s.
How fast will the foot be moving away from the wall when the top is 5m from the ground?

My answer:

use pythagoras to set up equation x^2 + y^2 = 13^2

Then I differentiate this implicitly and get the equation 2x dx/dt + 2y dy/t = 0

Then I fill in the values and get 5/6 m/s.

Is this correct?
 
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That is correct. I did it another way though, using a formula for dh/db.
 
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