Relation of EM radiation equation to radioactive decay

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SUMMARY

The discussion centers on the relationship between the electromagnetic radiation equation for an accelerating charged particle and radioactive decay, specifically focusing on gamma radiation. The equation presented is Erad = 1/(4πε0) * -qa⊥/c2r, which describes the radiating electric field. It is established that alpha and beta radiation, being particles with mass, do not relate to electromagnetic radiation, while gamma radiation, which consists of photons, is part of the electromagnetic spectrum and can originate from both the nucleus and orbiting electrons during radioactive decay. The transition of a nucleus from a higher energy state to a lower energy state releases gamma radiation, analogous to an electron emitting a photon when transitioning between energy levels.

PREREQUISITES
  • Understanding of electromagnetic radiation principles
  • Familiarity with radioactive decay processes
  • Knowledge of atomic structure and electron energy levels
  • Basic grasp of nuclear physics concepts
NEXT STEPS
  • Research the mechanisms of gamma radiation emission in nuclear decay
  • Explore the relationship between electron transitions and photon emission
  • Study the principles of accelerated charges and electromagnetic radiation
  • Investigate the energy states of atomic nuclei and their transitions
USEFUL FOR

Students and educators in physics, particularly those studying electricity, magnetism, and nuclear physics, as well as anyone seeking to understand the connections between electromagnetic radiation and radioactive decay processes.

zgoddard3
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Hello,

I am a Mechanical Engineering student but I am a TA for an electricity and magnetism course, and I had a student ask a question that's a little bit outside my understanding. The question was related to the equation for a radiating electric field from an accelerating charged particle:

Erad = 1/(4πε0) * -qa/c2r

This is an equation we always teach at the end of the course, but never go into much detail on it, and I myself have never really explored it much further.

The question my student asked was how this equation relates to radiation from radioactive elements. For alpha and beta radiation my answer was that they would not be related, since they are particles with mass, and not EM radiation. For gamma radiation, I was less sure. I remember from chemistry that excited electrons release a photon when falling back to a lower energy level. I was thinking that when the electron changes orbit it would have a sudden change in velocity causing the release of the EM wave. Is this on the right track and would anyone have a good answer that I could give to my student and future students who might have the same question?
 
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Accelerated charges generate EM radiation, a.k.a. photons. Radioactive decay produces alpha "radiation" (Helium nuclei), beta "radiation" (electrons and positrons), gamma "radiation" (photons) and neutrino "radiation". The EM radiation that is emitted when electrons jump to a lower orbit is not considered radioactivity as the aforementioned products of radioactive decay emanate from the nucleus.
 
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For alpha and beta radiation, that is what I thought. But gamma radiation is part of the electromagnetic spectrum, right? So where does it come from during radioactive decay?

A brief search seemed to indicate that gamma radiation during radioactive decay can come from the nucleus or orbiting electrons. For emission from electrons I figured that could be from a change in the orbit or that the gamma radiation could be released with a beta particle, since that electron would also undergo acceleration.

For gamma radiation from the nucleus, all I've found so far is that the gamma radiation is released to bring the nucleus from a higher energy state to a lower energy state, which sounds similar to a electron emitting a photon when moving from one energy level to the next. My question there is what signifies a higher energy state in a nucleus and how does it transition back to a lower energy state?
 
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