1. The problem statement, all variables and given/known data A passenger walks from one side of a ferry to the other as it approaches a dock. If the passenger's velocity is 1.90 m/s due north relative to the ferry, and 4.5 m/s at an angle of 33.0° west of north relative to the water, what are the direction and magnitude of the ferry's velocity relative to the water? _____ degrees west of north _____ m/s 2. Relevant equations Vfw = Vfp + Vwp theta (angle) = tan-1 (Ay/Ax) A (magnitude) = sqroot (Ax^2 + Ay^2) 3. The attempt at a solution Vfw = 1.9 ^y + (-4.5) cos (33) ^x theta = tan-1 (1.9 / -4.5 cost (33)) = -26.7 degrees magnitude = sqroot (1.9^2 + (-4.5 cos (33))^2) = 4.2 m/s I don't understand what I did wrong.