Relative velocity & Quantum mechanics (I think?)

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SUMMARY

The discussion centers on the calculation of relative velocity in a physics problem involving a plane and the behavior of water molecules during a phase change. The first question addresses the plane's speed relative to the air, concluding that the correct answer is 232 mph, derived from the formula for relative velocity, vair = vground - vwind. The second question examines the transition of water molecules from solid to liquid, with participants agreeing that the correct interpretation is that the molecules gain translational motion as they melt, contradicting the notion that nothing occurs during this phase change.

PREREQUISITES
  • Understanding of relative velocity concepts
  • Basic knowledge of phase changes in chemistry
  • Familiarity with trigonometric functions, specifically cosine
  • Ability to apply physics equations to real-world scenarios
NEXT STEPS
  • Study the derivation and application of the relative velocity formula vair = vground - vwind
  • Explore the kinetic molecular theory and its implications during phase changes
  • Learn about the effects of temperature on molecular motion in different states of matter
  • Investigate the role of trigonometry in physics, particularly in velocity and motion problems
USEFUL FOR

Students in physics and chemistry, educators teaching these subjects, and anyone interested in understanding the principles of relative motion and molecular behavior during phase transitions.

Subrosian
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1. The problem statements, all variables and given/known data
1. A plane leaves the ground and rises at an angle of 25º. If its speed relative to the ground is 210 mph, what is its speed relative to the air?

A. 232 mph
B. 210 mph
C. 190 mph
D. 89 mph

2. What happens to water molecules when they go from a solid to a liquid?

A. They slow down as ice melts.
B. Nothing.
C. They speed up as ice melts.
D. They get really cold as ice is formed.

Homework Equations


I'm not sure if any equations are necessary for either of the questions, but maybe
vair = vground - vwind

3. The attempt at solutions
I think the answer to the first question is B, because the air has no defined velocity and thus there should be no difference in relative velocity whether it's on the ground or in the air. However, I'm not sure if the fact that it rose to the air means that a vertical component is added to the plane's velocity, which would make the resulting velocity 210mph/cos(25), equivalent to 232mph (answer A.)

As for the second question, I don't think that C is true, because water molecules do not increase in temperature, and therefore speed, during change in state. What I learned in Chemistry is that the energy used during state change is used for breaking their intermolecular bonds. So I'm leaning towards B, but not exactly "nothing" is happening to the water molecules. Am I missing something?
 
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Subrosian said:
3. The attempt at solutions
I think the answer to the first question is B, because the air has no defined velocity and thus there should be no difference in relative velocity whether it's on the ground or in the air. However, I'm not sure if the fact that it rose to the air means that a vertical component is added to the plane's velocity, which would make the resulting velocity 210mph/cos(25), equivalent to 232mph (answer A.)
This is a poor question. The speed relative to a point on the ground is the same as the speed relative to the air, if there is no relative motion between the air and the ground. However, I suspect that they intended the 210 mph to be the horizontal speed of the plane relative to the ground, in which case your second answer would be correct.

As for the second question, I don't think that C is true, because water molecules do not increase in temperature, and therefore speed, during change in state. What I learned in Chemistry is that the energy used during state change is used for breaking their intermolecular bonds. So I'm leaning towards B, but not exactly "nothing" is happening to the water molecules. Am I missing something?
Again, a bad question. Obviously, "nothing" is not correct. I would say that C is the least incorrect. Although the kinetic energy of the molecules remains the same as the ice melts, the kind of motion changes. As ice, the molecules experience vibrational motion only. The bonds between water molecules prevent translational motion so they don't move around. After melting, the molecules have translational motion and can move around.

Good for you for noticing that these questions do not have correct answers.

AM
 
Subrosian said:
... which would make the resulting velocity 210mph/cos(25), equivalent to 232mph (answer A.)

Yes. I would take speed in air to be the instantaneous rate of change of displacement in air. This includes the z-axis. So ... A.
 

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