Relativistic Addition of Proton Velocities

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SUMMARY

The discussion centers on calculating the speed of a proton moving to the left at 0.70c relative to an electron moving to the right at 0.90c, both in the laboratory frame. The correct formula for relativistic velocity addition is Vx' = (Vx - V) / (1 - (v^2/c^2) * Vx), which was clarified during the conversation. Participants emphasized the importance of using the Lorentz transformation for accurate results, correcting an earlier miscommunication regarding the formula provided by the physics teacher.

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  • Understanding of relativistic physics concepts
  • Familiarity with the Lorentz transformation
  • Knowledge of velocity addition in special relativity
  • Basic algebra skills for manipulating equations
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  • Explore examples of Lorentz transformations in different frames
  • Learn about the implications of special relativity on high-speed particles
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Homework Statement



An electron moves to the right with a speed of 0.90c relative to the laboratory frame. A proton moves to the left with a speed of 0.70c relative to the electron. Find the speed of the proton relative to the laboratory frame.

Homework Equations



Vx'=[Vx-V]/[1+(v2/c2)*Vx]

The Attempt at a Solution



I have no idea where to start other than substituting 0.9c in for V.
 
Last edited:
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Using the Lorentz transformation for velocity is a perfectly fine approach. But that formula isn't correct. (Not even dimensionally.) So look up the correct formula.

Hint: Let the lab frame be the moving frame (primed) and let the proton's frame be the "stationary" frame (unprimed).

You can also just use the "addition of velocity" formula, which is derived from the Lorentz transformation (of course).
 
Ahh, got it. Our physics teacher gave us a slightly off formula, so it was cleared up today. Thanks!
 

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