Relativistic Hydrostatic Pressure in Constant Gravitational Field

[antoinebret]

Hi everybody,

When I have a perfect fluid within a constant gravitational field g, the pressure at depth z simply reads P=\rho g z, where \rho is the fluid density (incompresible).

If now my g is still constant, but my fluid is relativistic. Not because it's moving (everything is still) but because it is hot with k_B T \sim mc^2. What happens to P = \rho g z ?

Thanks!

 

[Mentz114]

Perfect fluids do not contain or conduct heat, so you have some other kind of fluid, perhaps ?

 

[Ich]

Perfect fluids do not contain or conduct heat

They do.

...it is hot with k_B T \sim mc^2. What happens to P = \rho g z ?

P= k_B T\rho_0/m + \rho g z with \rho=\gamma \rho_0.

You can use [ tex ] and [ /tex ] (click on the formula):
P=k_B T\rho_0/m + \rho g z

 

[Mentz114]

They do.

If you're right, I have been misinformed.

 

[Ich]

Ok, my comment was too general.
What I meant is that it makes sense to ask about a perfect fluid with a certain temperature in the way antoinebret did. From his data you can calculate energy density and pressure and answer the question with the perfect fluid behaviour, the extreme case being a photon gas.
I agree that there's no heat conduction, though.