I "relativistic mass" still a no-no?

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The discussion centers on the concept of "relativistic mass" and its relevance in modern physics, with a consensus leaning towards avoiding the term in favor of "invariant mass" and "relativistic momentum." Participants argue that when measuring mass in a relativistic context, one must specify the type of mass being measured, such as inertial or gravitational mass. The debate reflects a shift in educational approaches, where contemporary physics emphasizes a single mass definition, aligning with Newtonian concepts but clarifying distinctions in relativistic contexts. The conversation highlights the importance of using precise terminology to avoid confusion, especially given the evolving understanding of mass in both Newtonian and relativistic frameworks. Overall, the preference is for clarity and accuracy in discussing mass in the context of special relativity.
  • #91
I am closing the thread for moderation.
 
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  • #92
A number of off topic posts have been deleted and the thread is reopened.
 
  • #93
The whole thing could have been avoided had the old way of calling rest mass m0 and the relativistic mass m = γm0. Then E=mc2 would have survived, also centripetal force mv2/r. Like Regietheater opera, dumbing-down prevailed however. I was happy to see that even in the new millennial edition of Dr. Feynman's Lectures on Physics the editors decided to stick with what did not need fixin' 'cause it wasn't broke.
 
  • #94
rude man said:
The whole thing could have been avoided had the old way of calling rest mass m0 and the relativistic mass m = γm0. Then E=mc2 would have survived, also centripetal force mv2/r.

You cannot make the Newtonian expression ##\frac{mv^2}{r}## valid by replacing ##m## with the relativistic mass.

Like Regietheater opera, dumbing-down prevailed however. I was happy to see that even in the new millennial edition of Dr. Feynman's Lectures on Physics the editors decided to stick with what did not need fixin' 'cause it wasn't broke.

Feynman states that you can replace ##m## in the expressions of Newtonian physics with the relativistic mass and create relations that are valid. It's been discussed in the literature that such a notion is in general wrong. There are a few important and often-used relations where that can be done, but in the general case it's not valid.

In other words, it's an oversimplification.

The fact is, high energy physicists have never changed the practice of referring to only one kind of mass in their work and in their professional publications. Some of them, when authoring books and articles for the public, have used the concept of relativistic mass.

I'll leave it to you to decide which arrangement is a "dumbing down".

The main argument for doing away with it was indeed that it allowed survival of ##E=mc^2##. To people trying to learn physics it was obscuring the true meaning of Einstein's mass-energy relation. A misconception that often persisted into the professional phase of a physicist's life.
 
  • #95
rude man said:
The whole thing could have been avoided had the old way of calling rest mass m0 and the relativistic mass m = γm0. Then E=mc2 would have survived, also centripetal force mv2/r. Like Regietheater opera, dumbing-down prevailed however. I was happy to see that even in the new millennial edition of Dr. Feynman's Lectures on Physics the editors decided to stick with what did not need fixin' 'cause it wasn't broke.

The whole thing could have been avoided if Einstein and his contemporaries had stuck with either "mass" or "energy" for all mass/energy terms. Instead they adopted a confusing mishmash of various ##m##'s and ##E##'s.

There's nothing that ##m## quantifies that ##E## doesn't. They're the same quantity in different units.

There's nothing that ##m_0## quantifies that ##E_0## doesn't. They're the same quantity in different units.

Why we've ended up with ##E## and ##m_0## (now usually just called ##m##) is beyond me. I use ##E## and ##E_0##. If an answer is needed in mass units, I convert.
 
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  • #96
Mister T said:
You cannot make the Newtonian expression ##\frac{mv^2}{r}## valid by replacing ##m## with the relativistic mass.

You can. It's one of the special cases where it works. If you should it's another question.
 

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