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## Homework Statement

Show that

1/[itex]\sqrt{1-(u'/c)^2}[/itex]=[itex]\gamma[/itex](1-(vu/c^2)/[itex]\sqrt{1-(u/c)^2}[/itex]

## Homework Equations

## The Attempt at a Solution

Since I'm terrible with Latex I took a picture of what I have so far. I'm not sure where to go next or if I'm even on the right track.

My professor gave a hint that u'^2=(ux')^2+(uy')^2+(uz')^2

And that (u'/c)^2[itex]\Rightarrow[/itex]1-(u'/c)^2[itex]\Rightarrow[/itex] 1/(1-(u'/c)^2)^1/2

which I think just confused me more.

Thanks a lot

EDIT: Here's a link to the photo turned rightside up

http://i307.photobucket.com/albums/nn310/nilesthebrave/2012-09-27_20-22-26_35.jpg