Relativistic Particle in Circular Orbit

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SUMMARY

The discussion focuses on determining the magnetic field strength (b) for a charged particle of charge q and rest mass m0 moving in a circular orbit of radius R with angular frequency w. The participant correctly identifies the relationship between velocity (v), angular frequency (w), and radius (R) as v = wR. They also recognize the need to apply Newton's second law to relate the centripetal force to the particle's mass and acceleration. The participant initially struggled with the Lorentz factor but ultimately clarified the necessary equations for solving the problem.

PREREQUISITES
  • Understanding of circular motion and centripetal acceleration
  • Familiarity with Newton's second law of motion
  • Knowledge of electromagnetic theory, specifically the Lorentz force
  • Basic concepts of relativistic mechanics, including the Lorentz factor
NEXT STEPS
  • Study the derivation of the Lorentz force equation in electromagnetic theory
  • Learn about the application of Newton's laws in relativistic contexts
  • Explore the relationship between angular frequency and linear velocity in circular motion
  • Investigate the implications of relativistic effects on particle dynamics in magnetic fields
USEFUL FOR

Students and educators in physics, particularly those focusing on electromagnetism and relativistic mechanics, as well as anyone solving problems related to charged particles in magnetic fields.

SpaceTrekkie
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Homework Statement


A particle of charge q and rest mass m0 moves in a circular orbit of radius R and angular frequency w in a uniform magnetic field b in the z direction: Find b in terms of R,q , m0, and w.



Homework Equations


b = (1/c) v X e and v = w/R and e = not sure. My problem is that all of my equations for e have a gamma factor (lorentz factor) in them, and I don't think i need that. So I think I am using the wrong equations.



The Attempt at a Solution


I got that v = w/R
and if I do indeed use gamma i have gamma(u) = (1-w^2R^2/c^2)^-(1/2)
 
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Hi SpaceTrekkie! :smile:

(have an omega: ω Ω and a gamma: γ and try using the X2 tag just above the Reply box :wink:)
SpaceTrekkie said:
I got that v = w/R

erm :redface: … look at the dimensions …

v = L/T, R = L, ω = 1/T: v = ωR :rolleyes:

use good ol' Newton's second law … force = mass times centripetal acceleration :smile:
 
ooo ok, I was missing the part about that it will equation to F=ma. Ahh I feel dumb now. Thanks for your help!
 

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