PeterDonis
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Using the formulas I gave in post #30 just now, if we know the maximum rapidity ##\alpha##, the proper time ##T## required to reach it at proper acceleration ##a## is given byrocky said:the mass ratio calculations don't actually seem to support the top speeds required for the courses described in the book.
$$
T = \frac{\alpha c}{a}
$$
Plugging in ##\alpha = \ln 21## and ##a = 1.5 \text{g}##, I get ##T = 1.97## years. That looks consistent with the time you gave in the OP.
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