REQ Solution to differential equation

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Homework Help Overview

The discussion revolves around a differential equation involving second derivatives, specifically the equation \(\frac{c}{y^2}+k=y''\). The original poster expresses uncertainty about the solvability of the equation, having not yet studied differential equations.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore the possibility of solving the differential equation, with some suggesting initial approaches such as sketching solutions for simpler forms of the equation. Others question the existence of an analytical solution for the more complex equation.

Discussion Status

The discussion is ongoing, with participants sharing different perspectives on the solvability of the equation. Some guidance has been offered regarding potential methods of manipulation, but there is no consensus on the approach or solution.

Contextual Notes

The original poster has indicated a lack of background in differential equations, which may affect the depth of the discussion. There is also a mention of uncertainty regarding the analytical solvability of the equation.

Kurret
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Find the solution to [tex]\frac{c}{y^2}+k=y''[/tex]

I have not started with differential equations yet, so i have eno idea if its possible to solve, but i stumbled upon it when investigating a physics idea i got. Thanks for any help!
 
Last edited:
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uhm, could anyone just leave a comment if its possible to solve or not?
 
well we can first sketch a solution for y''=k which is y=kx^2/2+Ax+B
but for: y''y^2=c I don't think there's an analytical answer.
 
Multiply by y' and you'll be able to integrate both terms of the new equation.
 
bigubau said:
Multiply by y' and you'll be able to integrate both terms of the new equation.
How?? Cant make it work...
 

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