Resistance grows with temperature

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Homework Help Overview

The discussion revolves around the resistance of copper windings in an electric motor as it relates to temperature changes. The original poster presents a problem involving the calculation of temperature based on resistance values at different temperatures.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply a formula relating resistance and temperature to find the unknown temperature. Some participants question the accuracy of the book's provided answer and the calculations presented.

Discussion Status

The discussion includes attempts to verify calculations and address potential errors in the textbook. Participants express differing views on the correctness of the original poster's approach and the reliability of the book's information.

Contextual Notes

There is mention of a possible error in the textbook, and the original poster acknowledges a misunderstanding regarding the answer provided in the book.

Karol
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Homework Statement


The copper windings in an electric motor have a resistance of 54[Ω] at 200.
Later the resistance was 60[Ω], what is the temperature

Homework Equations


$$R_1=R_0(1+\alpha t_1)$$
α=0.00393[1/0]

The Attempt at a Solution


At 00C R0 is: ##54=R_0(1+0.00393\cdot 20)\rightarrow R_0=50.06##
##60=50.06(1+0.00393\cdot t_2)\rightarrow t_2=50.5^0##
It should be t2=2860C
 
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And your question is what?
 
If i am right and the book is wrong.
 
Your math looks good. Books have been known to be in error.
 
Thanks and now i saw i read the wrong answer in the book, but thanks anyway for the effort
 

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