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I am a little bit confused about this problem. I couldn't find any other post that could help me, so I am posting here for the first time.

Consider a layer (sheet) of resistive material, in which it's shape resembles a trapezium. What is the resistance between two electrodes placed on the "tilt" sides? The resistance of the electrodes is assumed to be very low compared to the other material

Well, for a squared-shape geometry with two electrodes in two opposite sides, I know that

dR = Rsheet * dx/b

- Rsheet is the sheet resistance of the material

- dR is the infinitesimal resistance

- x is the horizontal axis

- y is the vertical axis

- a is a value along the x axis

- b is a value along the y axis

The result is well-known, R = Rhseet * (a/b), where (a/b) is a geometrical factor.

By symmetry, for this squared shape geometry, no current flows along the "y" direction so turning the problem into a 1D. Not very complicated.

Now, returning to the trapezoidal geometry, I am not so sure if the problem is still going to be 1D. I am guessing there will be some current flowing in the "y" direction, namely "Iy". Also, not sure how to deal with the two extra triangles on each side of the contacts.

I appreciate any contributions or directions.

Thank you