1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Resistance of each IDENTICAL resistor?

  1. Sep 17, 2007 #1
    1. The problem statement, all variables and given/known data
    The circuit in the drawing contains five identical resistors. The V = 50 V battery delivers 46 W of power to the circuit. (Picture should show up somewhere)

    Q: what is the resistance in each resistor

    2. Relevant equations

    so far the only things i have thought of is P = IV...which gives me I...and I = V/R

    3. The attempt at a solution

    I use the above equations to get to a Total resistance of 54.3 ohms...

    i thought of several different ways to go about it from there and none of them have worked. dividing by 5 not going to work...
    tried multiplying by 4 and dividing by 5 (5 total resistors, but when we add them in parallel we only have 4 being added into the total since two are in series).

    anyways...basically i am lost...i've gotten through all 17 problems on the hw and cannot really think this one through...its 3:30 a.m....any help would be GREATLY appreciated!

    1. The problem statement, all variables and given/known data

    2. Relevant equations

    3. The attempt at a solution

    Attached Files:

  2. jcsd
  3. Sep 17, 2007 #2


    User Avatar

    Staff: Mentor

    P = IV so use I = P/V to get I.

    Then one has to find the resistances using V = IR.

    So all resistors have same resistance R, but the total resistance is not 5R or 4R.

    So one has to find the equivalent resistor noting that R3 and R4 are in series, so the combined resistance is 2R.

    Then that 2R is parallel (||) with R2 and R5. So find the equivalent resistance of that combination.

    Then that combination is in series with R1, so the total resistance is R1 + Req(R2 + R3||R4 + R5), with each resistance being the same R.
    Last edited: Sep 17, 2007
  4. Sep 17, 2007 #3
    First determine the equivalent resistance of the circuit. R3 and R4 are in series. Hence they add up to (R3 + R4) = 2R (where R is the value of each resistance in ohm). This 2R, R2 and R5 are in parallel. Determine their equivalent value using the relevent formula. Then this equivalent resistance is in series with R1. Add them up to get the equivalent resistance of the circuit (Reqv). Reqv will be in terms of R.

    Power consumed = V^2/Reqv . As V is given, Power is given and Reqv is in terms of R, solve to get value of R.
  5. Sep 17, 2007 #4

    Ok got it...took a moment to figure out the addition of the fractions in parallel...but sure enough it worked :)

    I think the V^2 / R = P was the part that cracked it for me. P = IV wasn't seeming to swing it for me :)

    In case anyone else needs it and for someone else to double check that I didn't do this wrong some how:

    i did 1/r + 1/2r + 1/r = 5/2r ohms^-1 = 2R/5 ohms + R = 7R / 5

    50^2 *5 / 46 = 7R

    R = 38.82 Ohms

    Thanks again to both of you!
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?