Resistor Shorting and Kirchhoff's Rule Explanation

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AI Thread Summary
When the 18 Ω resistor is shorted out, it effectively becomes a wire with zero resistance, which can alter the circuit's behavior. Despite being shorted, it is important to consider its presence in the circuit for applying Kirchhoff's rules correctly. The confusion arises because omitting the shorted resistor can lead to incorrect calculations of current. The correct approach involves analyzing the circuit with the shorted resistor to understand the overall current distribution. Including the shorted resistor in the analysis helps clarify how the current flows through the remaining components.
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Homework Statement


What would the current I1 be in the figure below if the 18 Ω resistor is shorted out (resistance = 0)? Let r = 1.0 Ω.

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Homework Equations


I used Kirchhoff's Rule

The Attempt at a Solution


I figured this problem out, but I had trouble, and I'm not sure I understand why the answer is what it is. I'm confused about the resistor shorting out. At first, I wrote out the problem not including the shorted out resistor, as the resistance became 0 when it shorted out. However, this was wrong. I then attempted the problem including the 18 ohm resistor, and I got the correct answer.

Can someone explain to me why you need to include the shorted out resistor?

Note: I simply want to understand why, I don't need the problem worked out, as I already found the numerical answer.
 
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You had it right the first time. If the resistor is shorted, it should not be included in the calculations. It sounds like the solutions you were given might be incorrect.
 
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