Resonace frecuency and peak current

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The discussion centers on calculating the resonance frequency and peak current in an RLC circuit. The user applied the formula \(2\pi f L = \frac{1}{2\pi f C}\) to determine the resonance frequency, arriving at a value of 5032.92 Hz. Another participant confirmed the calculation as correct, indicating that the frequency is indeed plausible given the circuit parameters. The focus is on understanding resonance conditions where the inductive reactance (XL) equals capacitive reactance (XC).

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Xaspire88
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For the circuit shown
a. What is the resonance frequency?
b. At resonance, what is the peak current through the circuit?

http://img218.imageshack.us/img218/2971/p56dr3.png

I solved for resonance frequency knowing that when Xc=XL you get a resonance frequency.
my set up was

2pifL=1/(2pifC)

and then i solved for f... but the number i got was 5032.92 and this seems way too big.
 
Last edited by a moderator:
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Please help me out. Thank you.:cry:
 
I think your calculation of the frequency is correct.
 

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