Revolution Volume by Cylinder Shells

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SUMMARY

The discussion focuses on calculating the volume of a solid of revolution formed by rotating the region enclosed by the curves y=e^x and y=1/x, between x=1 and x=2, about the x-axis using the cylindrical shells method. The upper curve is identified as y=e^x and the lower curve as y=1/x. The formula for the surface area of the cylindrical shell is established as 2πx(e^x - 1/x), which is then multiplied by the thickness dx to derive the differential volume. Clarification is provided regarding the radius of the cylinder being equal to x, not y, when using this method.

PREREQUISITES
  • Understanding of the cylindrical shells method for volume calculation
  • Familiarity with the curves y=e^x and y=1/x
  • Knowledge of integral calculus and differential volume concepts
  • Ability to set up and evaluate definite integrals
NEXT STEPS
  • Study the cylindrical shells method in detail, focusing on its application in volume calculations
  • Practice setting up integrals for various curves and regions of rotation
  • Explore the comparison between the cylindrical shells method and the disk/washer method
  • Learn how to apply the method of cylindrical shells to other functions and boundaries
USEFUL FOR

Students and educators in calculus, particularly those focusing on solid geometry and volume calculations, as well as anyone seeking to deepen their understanding of integral applications in real-world scenarios.

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Rotate about x-axis the region enclosed by y=e^x, y=1/x, x=1 and x=2. I can do the problem with the rings method but I don't how to even set up the integral to solve by the shells method. Help? Thanks
 
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The two curves cross well before x= 1 so you have a region in which y=ex is the upper curve and y= 1/x is the lower. That means that the length of your cylinder is exx- 1/x. The radius is x so you cylinder will have a surface area, for each x, of [itex]2\pi x(e^x- 1/x)[/itex]. Multiply that by the "thickness", dx, to find the differential of volume.
 
Thanks, but since the region enclosed by the boundaries given is rotated about the x-axis, then, doesn't it mean that the radius of the cylinder is y? I'm a little confused. ??
 

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