MHB Riemann Integration - The Additivity Theorem .... B&S Theorem 7.2.9 ....

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The discussion centers on the confusion regarding the notation of tagged partitions $$\dot{ \mathcal{P} }$$ and $$\dot{ \mathcal{Q} }$$ in the proof of Theorem 7.2.9 from "Introduction to Real Analysis" by Bartle and Sherbert. A participant suggests that there may be a misprint, proposing that the sentence should refer to $$\dot{ \mathcal{Q} }$$ instead of $$\dot{ \mathcal{P} }$$. The complexity of the proof is highlighted, particularly how the definition of integrals relies on approximating partitions that may or may not include certain points. This intricacy contributes to the overall difficulty of understanding the theorem. The discussion emphasizes the need for clarity in mathematical texts, especially in challenging proofs.
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I am reading "Introduction to Real Analysis" (Fourth Edition) by Robert G Bartle and Donald R Sherbert ...

I am focused on Chapter 7: The Riemann Integral ...

I need help in fully understanding an aspect of the proof of Theorem 7.2.9 ...Theorem 7.2.9 and its proof ... ... read as follows:View attachment 7319
https://www.physicsforums.com/attachments/7320In the above proof (near to the start ...) we read the following:

" ... let $$\dot{ \mathcal{P} }$$ be a tagged partition of $$[a, b]$$ with $$ \lvert \lvert \dot{ \mathcal{Q} } \lvert \lvert \ \lt \delta $$. ... ... "I am somewhat puzzled by B&S's use of $$\dot{ \mathcal{P} }$$ and $$\dot{ \mathcal{Q} }$$ in this proof ... can someone please explain the use of these symbols ... I know they are different partitions ... but why does B&S introduce them ... what is the logic ... why do we need both ... ... [ ... the use of both $$\dot{ \mathcal{P} }$$ and $$\dot{ \mathcal{Q} }$$ in the particular statement I quoted seems to me to be most peculiar ... ]

PeterIt may help readers of the above post to have reference to the notation of B&S in setting up the Riemann Integral ... so I am providing the text of Section 7.1 up to and including the definition of the Riemann Integral ... as follows ...View attachment 7321
https://www.physicsforums.com/attachments/7322
https://www.physicsforums.com/attachments/7323
 
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Peter said:
In the above proof (near to the start ...) we read the following:

" ... let $$\dot{ \mathcal{P} }$$ be a tagged partition of $$[a, b]$$ with $$ \lvert \lvert \dot{ \mathcal{Q} } \lvert \lvert \ \lt \delta $$. ... ... "I am somewhat puzzled by B&S's use of $$\dot{ \mathcal{P} }$$ and $$\dot{ \mathcal{Q} }$$ in this proof
It looks to me as though you have identified another misprint in Bartle and Sherbert. The only way I can make sense of it is that the above sentence should read
" ... let $$\color{red}\dot{ \mathcal{Q} }$$ be a tagged partition of $$[a, b]$$ with $$ \lvert \lvert \dot{ \mathcal{Q} } \lvert \lvert \ \lt \delta $$. ... ... "
It is particularly unfortunate that there should be an error in what the authors admit is a tricky and delicate proof. The fact that $$\int_a^bf = \int_a^cf + \int_c^bf$$ ought to be straightforward. But the integrals are defined in terms of approximating partitions, and a partition of $[a,b]$ may or may not include $c$ as one of its partition points. That is the root cause of the technical difficulties that make this such a complicated and obscure proof.

Bartle and Sherbert would have done well to employ you as a proofreader! (Rofl)
 
We all know the definition of n-dimensional topological manifold uses open sets and homeomorphisms onto the image as open set in ##\mathbb R^n##. It should be possible to reformulate the definition of n-dimensional topological manifold using closed sets on the manifold's topology and on ##\mathbb R^n## ? I'm positive for this. Perhaps the definition of smooth manifold would be problematic, though.

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