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Ring problem: nilpotent elements and units

  • Thread starter rachellcb
  • Start date
  • #1
10
0

Homework Statement


Let R be a ring with multiplicative identity. Let u [itex]\in[/itex] R be a unit and let a1, ..., ak be nilpotent elements that commute with each other and with u. To show: u + a1 + ... + ak is a unit.

The Attempt at a Solution


Need to show that u'(u + a1 + ... + ak)=1 for some u' [itex]\in[/itex] R.
I know that 1 - ai is a unit (i=1,2,...,k) since each ai is nilpotent.
So i'm trying to think of possible candidates for u'.
My attempt so far have been to try and cancel the ai terms by multiplying
u + a1 + ... + ak by a1n-1, where a1n =0 and so on for all all a_i but this leaves me with ua1n-1...akm-1 and doesn't seem to be leading anywhere...
Any suggestions?
 

Answers and Replies

  • #2
jgens
Gold Member
1,581
50
Show first that the sum of two nilpotent elements which commute with each other is nilpotent (Hint: Generalize the binomial theorem to an arbitrary ring). Then use induction to show that the sum of k nilpotent elements which commute with each other is nilpotent. Then lastly prove that the sum of a nilpotent element and a unit is a unit (Hint: This is similar to proving 1+x is a unit, where x is nilpotent).
 
  • #3
10
0
Solved, thanks! :smile:
 

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