Ring with Unity: Subrings Isomorphic to Z & Z_m

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Homework Help Overview

The discussion revolves around the properties of rings with unity, specifically focusing on whether a ring can contain two subrings isomorphic to different integers Z_n and Z_m, where n does not equal m. The original poster seeks to understand the implications of Corollary 27.18 from Farleigh regarding subrings in such rings.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster expresses an intuition that it may be impossible for a ring to contain two distinct subrings isomorphic to Z_n and Z_m. Other participants explore examples, such as Z/8Z, and question the nature of subrings and their isomorphisms. There are discussions about the definitions of subrings and the conditions under which they hold.

Discussion Status

Participants are actively engaging with the problem, raising questions about specific examples and definitions. Some have provided examples and counterexamples, while others are clarifying terminology and exploring the implications of their definitions. There is no explicit consensus yet, as various interpretations and examples are being considered.

Contextual Notes

There are ongoing discussions about the definitions of subrings and whether they must contain a unit. The original poster's edit indicates a clarification in the question posed, which may affect the direction of the discussion.

ehrenfest
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[SOLVED] rings with unity

Homework Statement


Corollary 27.18 (in Farleigh) tells us that every ring with unity contains a subring isomorphic to either Z or some Z_n. Is it possible that a ring with unity may simultaneously contain two subrings isomorphic to Z_n and Z_n with n not equal to m? If it is possible, give an example. If it is impossible, prove it.

EDIT: change the second Z_n to Z_m

Homework Equations


The Attempt at a Solution


My intuition tells me it is impossible. But I have no idea how to prove it.
 
Last edited:
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What about Z/8Z? All of its subrings are isomorphic to some Zn. Does that mean all its subrings are isomorphic to each other?
 
ehrenfest: Given that the meanings you give to the words is not the most common, you really need to be specific about their meaning.

e.g. I have absolutely no idea if, in this particular context, your use of 'subring' in this context requires the subring to contain a unit, and if that unit has to be the same as the one in the enclosing ring.
 
A ring <R,+,*> is a set R together with two binary operations + and * such that the following axioms are satisfied:
1) <R,+> is an abelian group
2) Multiplication is associative
3) For all a,b,c in R, a*(b+c)=(b+c)*a=a*b+a*c

A subring is a subset of a ring that is also a ring.

See the EDIT.

Yes. I see. Z_8, we have the subring {0,4} which isomrphic to Z_2 and the whole ring is also a subring.
 
Last edited:
ehrenfest said:
A ring <R,+,*> is a set R together with two binary operations + and * such that the following axioms are satisfied:
1) <R,+> is an abelian group
2) Multiplication is associative
3) For all a,b,c in R, a*(b+c)=(b+c)*a=a*b+a*c

A subring is a subset of a ring that is also a ring.

See the EDIT.

Yes. I see. Z_8, we have the subring {0,4} which isomrphic to Z_2 and the whole ring is also a subring.
The subalgebra {0, 4} of Z_8 is not isomorphic to Z_2.
 
Last edited:
Why?
4+4=0
0+4=4
0+0=0
4*4=0
4*0=0
0*0=0

This is the same algebra as Z_2.

EDIT: you're right 1*1=1 not 0
EDIT: then what subring of Z_8 is isomorphic to Z_n where n is not equal to 8?
 
Last edited:
Oops, that example doesn't work. Try Z_4 X Z_2.
 
Then we have subrings isomorphic to Z_2 and Z_4. Thanks.
 
is the ring Zn the same as the ring Z/Zn? (the one whose elements are modulo equivalence classes, with regular summation and multiplication?)
 
  • #10
jacobrhcp said:
is the ring Zn the same as the ring Z/Zn? (the one whose elements are modulo equivalence classes, with regular summation and multiplication?)

Yes, they are isomorphic since the kernel of

phi: Z -> Z_n defined by phi(z) = z mod n

is Zn.
 
  • #11
no I meant if Zn was defined in that way >_>

but it's not ... but almost. Thanks anyway. =)
 
  • #12
jacobrhcp said:
but it's not ... but almost.

What do you mean?
 

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