Rocket launch that produces a certain g-force

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SUMMARY

The calculation of g-force during a rocket launch is determined by acceleration rather than velocity. Specifically, one g of acceleration equals 9.8 meters per second squared (9.8 m/s²). The correct formula to calculate the perceived g-force is (a/g) + 1, where 'a' represents the acceleration experienced by the rocket. This formula accounts for the additional force felt due to the rocket's acceleration beyond the standard gravitational pull.

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How do you calculate the period during rocket launch that produces a certain g-force? Is there a formula to work this out?
 
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My apologies HallsofIvy. I've been experiencing ISP issues and getting bumped repeatedly, so I typed up what I thought may have been the "quick and easy" explanation, posted it, and didn't have a chance to thoroughly recheck it before I got bumped again. It took me the last 20 minutes or so just to get reconnected.
 
Last edited:


It will depend on each specific situation. One g of acceleration is about 9.8 meters per second per second. 9.8m/s^2

So at the point in the launch the rockets speed is changing by 9.8m/s^2 the craft is experiencing one g over and above the acceleration due to gravity.
 


? G force has nothing to do with velocity- it depends on acceleration. Was that just a repeated misprint? (Referring to Gnosis' post.) The formula should be (a/g)+ 1, not (v/g)+ 1. That is, you feel your normal weight due to gravity plus an additional "weight" due to the force causing the acceleration.
 

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