Rocket physics equation problem

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The discussion focuses on deriving the mass equation for a rocket with a constant mass ejection rate, expressed as m = m0(1 - kt). The user attempts to relate the mass loss equation, dm/dt = -k m0, to the dynamics of the rocket's motion, specifically the equation -mg = m(dv/dt) - Vr(dm/dt). They express confusion about integrating the mass loss equation and how it connects to the rocket's motion. The integration of the mass loss equation is crucial for demonstrating the relationship between mass and time in the context of rocket physics. Clarification on the integration process and its implications for the motion equation is sought.
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Suppose the rate of ejection mass by a rocket is a constant, dm/dt = -kmo. I need to show that m=mo(1-kt). I know -mg=m(dv/dt)-Vr(dm/dt). I thought that I could just substitute for (dm/dt) and get the solution but I am having no luck. Please help me show this property.
 
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You need to integrate the equation given to you for the mass loss

\frac{dm}{dt} = -k m_0 \implies \int_{m_0}^{m(t)}dm = - k m_0 \int_0^t dt'
 


My question is how does this relate to the equation that I posted? aka: -mg=m(dv/dt)-Vr(dm/dt)
 


Do I have the right equation?
 
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