Rolling without slipping problem

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Homework Help Overview

The problem involves a solid sphere rolling without slipping down a ramp inclined at 32 degrees to the horizontal. Participants are discussing the acceleration of the sphere's center of mass as it rolls down the ramp, with a focus on the forces and torques involved in the motion.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the relationship between gravitational force, torque, and acceleration. Questions arise regarding the role of friction and the necessity of mass or coefficient of friction in calculations. Some participants suggest reconsidering the application of Newton's laws and the conditions for rolling without slipping.

Discussion Status

The discussion is active, with participants providing hints and corrections regarding the application of torque and inertia. There is recognition of the need to analyze the problem from different points of view, particularly regarding the point of contact and the forces acting on the sphere.

Contextual Notes

Participants note the absence of mass and coefficient of friction in the problem setup, which raises questions about how to proceed with calculations. There is an acknowledgment of the complexities involved in applying the principles of rotational dynamics and translational motion.

ph123
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A solid sphere rolls without slipping down a ramp that is at an angle of 32 above horizontal. The magnitude of the acceleration of the center of mass of the sphere as it rolls down the ramp is?


sum of torques = I(alpha)

rmgsin32 = (2/5)mr^2(a_tan/r)

the radii drop out as one would expect with no radius given. the masses also drop out since they weren't provided.

gsin32 = (2/5)a_tan

(9.8 m/s^2)sin32 = (2/5)a_tan

a = 12.98 m/s^2

This result clearly makes no sense because it is greater than the accelertion due to gravity. But that was the only approach I could think to use since I was only given the angle of the incline. Any ideas?
 
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Hints: Does gravity exert a torque on the sphere? What other force acts on the sphere that exerts the torque?
 
friction. but how can I calculate friction without mass or coefficient of friction?
 
ph123 said:
friction. but how can I calculate friction without mass or coefficient of friction?
Just try it--maybe you won't need that information. :wink:

Apply Newton's law for translation and rotation. And the condition for rolling without slipping.
 
omg duh. i forgot about the forces in the x-direction. i always do that. thanks.
 
ph123 said:
sum of torques = I(alpha)

rmgsin32 = (2/5)mr^2(a_tan/r)

The second line is not correct. On the left hand side, you wrote the torque around the center which is the point where the sphere touches the slope, so you need to use inertial momentum I corresponding to the axis through above point.

On the right-hand side, it should be

I=2/5mr^2+mr^2=7/5 mr^2 (axis-parallel theorem, or Steiner's theorem)
 
That's perfectly OK as well: Since the sphere rolls without slipping, you can view it as being in pure instantaneous rotation about the point of contact. With this approach, you need to use torques and rotational inertia about the point of contact, not about the center. Note that gravity does exert a torque about the point of contact. (I find the two step approach--analyzing translation and rotatation separately--to be more instructive. But it's all good! :smile: )
 
Yes Doc Al, that's what I meant.
 

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