Roots of a third degree polynomal equation (complex numbers)

In summary, the problem involves finding the other roots of the equation z^3+az^2+bz+c where a, b, and c are real numbers and one root is given as 1+3i. By plugging in this root and its conjugate, 1-3i, into the equation, we can solve for a, b, and c. The third root must be real and can be found by considering the triangle formed by the roots in the complex plane, with an area of 9 units. By using the formula for the area of a triangle, we can determine that the third root must be either -2 or 4.
  • #1
hrappur2
9
0
Hey everyone! Here I have a problem I don't know how to solve so help would be greatly appreciated!

Homework Statement


Here is an equation z^3+az^2+bz+c where a, b and c are real numbers. If the roots are drawn in the complex plane they form a triangle with area of 9 units. One root of the equation is 1+3i.

(a) Find other roots of the equation.
(b) Find a, b and c2. The attempt at a solution
The only thing I know is that if 1+3i is a root than 1-3i is also a root but more I don't know, I have no idea how to solve this without a, b and c i don't know how to find them.

-Thanks in advance!

EDIT: I think I finally figured out how to solve this. I tried to insert (1+3i) and (1-3i) into the equation and got a=1, b=4 and c=30 then I put it in the original equation and get the third root, z=-3. Is that correct? What is confusing me is that the area has to be 9, I don't get that.
 
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  • #2
hi hrappur2! :smile:
hrappur2 said:
EDIT: I think I finally figured out how to solve this. I tried to insert (1+3i) and (1-3i) into the equation and got a=1, b=4 and c=30 …

how? :confused:

it might be easier to start with the triangle …

you know the position of one of its sides …

so what line does the opposite point have to be on if the area is 9 ? :wink:
 
  • #3
Unfortunately, I can't see the equation itself but yes, if the equation has only real coefficients and 1+ 3i is a root then 1- 3i is another root and the third root must be real. The fact that it is real means it is at the point (x, 0) in the complex plane for some real number x. Can you determine the area of such a triangle, in terms of x?

Note tiny-tim's suggestion. The area of a triangle is "base times height" and we can take the line through 1+ 3i and 1- 3i ((1, 3) and (1, -3)) as base. What is its length? Knowing that and the fact that the area is 9, we can find the height of the triangle. The third vertex must lie on a line parallel to the line through (1, 3) and (1, -3) and a distance equal to the height of the triangle from it.
 
  • #4
Thanks a lot for your help!

So if I'm understanding this correctly I draw 1-3i and 1+3i into the plane and get that the base is 6 so I have to have height 3 so the area is 9. So the third root must be either -2 or 4. Is that correct?
 
  • #5
yes, the third root must be real, so it's -2 or 4 :smile:
 

FAQ: Roots of a third degree polynomal equation (complex numbers)

What is a third degree polynomial equation?

A third degree polynomial equation, also known as a cubic equation, is an algebraic equation of the form ax^3 + bx^2 + cx + d = 0, where a, b, c, and d are constants and x is the variable.

What are the roots of a third degree polynomial equation?

The roots of a third degree polynomial equation are the values of x that make the equation equal to 0. Depending on the coefficients and the nature of the equation, there can be one, two, or three distinct roots.

How do you find the roots of a third degree polynomial equation?

To find the roots of a third degree polynomial equation, one can use the cubic formula or synthetic division to factor the equation. Additionally, the Rational Root Theorem can be used to determine possible rational roots which can then be tested to see if they are indeed roots of the equation.

What are complex roots?

Complex roots are solutions to a polynomial equation in which the roots involve the use of imaginary numbers. For a third degree polynomial equation, if there are three complex roots, they will come in the form of a + bi, where a and b are real numbers and i is the imaginary unit (defined as the square root of -1).

How do you graph a third degree polynomial equation with complex roots?

To graph a third degree polynomial equation with complex roots, one can plot points by substituting different values of x into the equation. The resulting points can then be connected to form the graph. Additionally, using a graphing calculator can provide a more accurate and detailed graph of the equation.

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