Roots of Trigonometric Functions in an Interval

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SUMMARY

The discussion focuses on proving that the function y = A cos x + B sin x has at least n zeroes within the interval [π, π(n+1)], where n is an integer. The key approach involves transforming the function into the form y = √(A² + B²) cos(x + α), where α = -arccos(A/√(A² + B²)). The periodic nature of sine and cosine functions is essential in establishing the number of zeroes in the specified interval. This method leverages trigonometric identities and properties of periodic functions to derive the conclusion.

PREREQUISITES
  • Understanding of trigonometric functions and their properties
  • Familiarity with the concept of periodicity in functions
  • Knowledge of trigonometric identities, specifically the transformation of sine and cosine
  • Basic skills in calculus, particularly in analyzing functions for zeroes
NEXT STEPS
  • Study the derivation and application of trigonometric identities
  • Learn about the periodic properties of sine and cosine functions
  • Explore the implications of the Intermediate Value Theorem in trigonometric contexts
  • Investigate the graphical representation of trigonometric functions to visualize zeroes
USEFUL FOR

Students in mathematics, particularly those studying trigonometry and calculus, as well as educators seeking to enhance their understanding of function behavior in specified intervals.

Ted123
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Homework Statement



This isn't really a question on its own, rather a step in the solution to another question:

How would I prove that [tex]y= A\cos x + B\sin x[/tex] (A, B arbitrary constants) has at least [tex]n[/tex] zeroes in the interval [tex][\pi , \pi (n+1)][/tex] where [tex]n\in\mathbb{Z}\;?[/tex]

(I don't need to be too explicit about it)

I was thinking state that [tex]A\cos x + B\sin x = \sqrt{A^2+B^2}\cos (x + \alpha)[/tex] [tex]0\leq\alpha \leq 2\pi[/tex] and say something about periodicity and when sine and cosine are + or -...
 
Last edited:
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Should be it. Don't forget to mention that α = -arccos(A/sqrt(A²+B²)).
 

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