Rotaional Inertia of a Thin Rod

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To calculate the rotational inertia of a meter stick with a mass of 0.68 kg about an axis at the 21 cm mark, the approach involves treating the stick as a thin rod. The relevant equation for rotational inertia is I = integral of r squared with respect to mass. By assuming constant density, the mass differential can be expressed as dm = pdV, where p is the density and dV is the volume element. The discussion suggests manipulating this equation to find the mass as a function of distance from the axis. The conversation focuses on deriving the correct expression for the rotational inertia based on these principles.
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Homework Statement


Calculate the rotational inertia of a meter stick, with mass 0.68 kg, about an axis perpendicular to the stick and located at the 21 cm mark. (Treat the stick as a thin rod.)


Homework Equations


I = integral of r squared with respect to mass


The Attempt at a Solution


?
 
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Oijl said:

Homework Statement


Calculate the rotational inertia of a meter stick, with mass 0.68 kg, about an axis perpendicular to the stick and located at the 21 cm mark. (Treat the stick as a thin rod.)


Homework Equations


I = integral of r squared with respect to mass


The Attempt at a Solution


?

so you want to find the mass of the object as a function of the distance from the axis. We can assume the the density is constant, so we could write:

dm = pdV

where dm is the mass differential from the integral, p the density (a constant) and dV the volume.

But some parts of the volume are constant, so you can further manipulate this equation. Can you see where to go from here?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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