Rotating wheel initial angular velocity given final and time

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SUMMARY

The discussion focuses on calculating the initial angular velocity of a rotating wheel that completes 37 revolutions in 3.0 seconds, with a final angular speed of 98 rad/s. The average angular velocity is determined using the formula for average omega, calculated as (37 * 2π) / 3. The initial angular velocity is derived by subtracting the angular velocity at 1.5 seconds from the average angular velocity, resulting in an initial speed of 56.89 rad/s. Alternative methods using angular kinematics equations are also discussed, confirming the validity of the calculations.

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Homework Statement


A rotation wheel required 3.0 s to complete 37 revolutions. its angular speed at the end of the 3.0 s interval is 98 rad/s. what was the original angular speed of the wheel?


Homework Equations


average omega = change in angle/change in time


The Attempt at a Solution



heres my thought on the answer, i wanted to make sure its right since i don't have the correct answer to compare my thoughts

i find the average angular velocity by 37*2pi over 3
since the acceleration is constant the average angular velocity is at 1.5 s
so then i find the difference between final angular velocity which is at 3 seconds and the velocity at 1.5 seconds which is 20.51 and subtract that from the average angular velocity to get the angular velocity at 0 seconds.

the final answer is 56.89 since the velocity at 1.5 seconds is 77.49

is this thought process correct, it seems to be from my point of view.
 
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That works (though you should check your final answer, it looks like you have a couple digits flipped around.

You can also do this with

\omega_f^2 = \omega_i^2 + 2 \alpha \Delta \theta
and
\alpha = \frac{\omega_f - \omega_i}{\Delta t}

I think your way is probably simpler, but requires breaking the problem into two steps. However, you do avoid having to solve a quadratic equation.
 
right, 56.98 rad/s

Thanks!
 

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