Rotational Inertia Hill Problem

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SUMMARY

The discussion focuses on calculating the linear speed of a bicycle wheel rolling down an 8-meter hill, starting with an initial speed of 0.5 m/s. The relevant equations include the moment of inertia \(I = \frac{1}{2}mr^2\) and the conservation of energy principle, which states that the sum of kinetic energy (KE) and potential energy (PE) remains constant. Participants emphasize the need to incorporate both linear and rotational kinetic energy in the calculations to find the final linear speed at the bottom of the hill.

PREREQUISITES
  • Understanding of rotational inertia and its formula \(I = \frac{1}{2}mr^2\)
  • Knowledge of conservation of energy principles in physics
  • Familiarity with kinetic energy equations, including linear and rotational components
  • Basic algebra skills for solving equations
NEXT STEPS
  • Study the conservation of mechanical energy in rolling motion
  • Learn how to derive the final linear speed from potential energy and kinetic energy equations
  • Explore the relationship between linear speed and rotational speed in rolling objects
  • Investigate the effects of initial conditions on the final speed of rolling objects
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of rolling motion and energy conservation principles in mechanics.

cnfsdstudent
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A bicycle wheel is rolled down a hill that is 8 m high, Determine the linear speed of the wheel at the bottom of the hill if the wheel is moving initially at .5 m/s


I= 1/2mr^2

mgh=1/2mv^2



I know it is set up like a KE equation, and I also know I am missing a variable to solve for on the mgh side. Does anyone know what that variable might be? I know it isn't torque.
 
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Welcome to PF!

Hi cnfsdstudent! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)

You need KE + PE = constant, and also KE = linear KE + rotational KE. :smile:
 

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