Rotational Inertia, Torque and Angular Acceleration (1Q)

AI Thread Summary
The discussion centers on calculating angular acceleration for a 5 kg solid sphere with a radius of 0.6 meters when a force of 3 N is applied perpendicularly. The initial calculation incorrectly used the moment of inertia formula for a solid sphere, which should be I = (2/5)MR² instead of I = MR². The correct angular acceleration is derived from the torque equation, leading to a different result than initially stated. Additionally, the moment of inertia for a hollow sphere is confirmed to be I = (2/3)MR². Accurate understanding of these concepts is essential for solving related physics problems effectively.
Sam Cepeda
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Homework Statement



. What is the angular acceleration if a force of 3 N is applied perpendicular to the radius of a 5 kg solid sphere that has a radius of 0.6 meters?

Homework Equations


tauv.gif
= r x F
I = mr^2


The Attempt at a Solution


I used
9be08b9254aaacbc0386b26bf137f2ae.png

tried solving for angular acce.
3N/(5kg)(0.6) =10rad/sec^2

Also, if the question had said "hollow sphere" would the moment of inertia be different..(2/3)mr^2 ?
 
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Sam Cepeda said:

Homework Statement



. What is the angular acceleration if a force of 3 N is applied perpendicular to the radius of a 5 kg solid sphere that has a radius of 0.6 meters?

Homework Equations


tauv.gif
= r x F
I = mr^2


The Attempt at a Solution


I used
9be08b9254aaacbc0386b26bf137f2ae.png

tried solving for angular acce.
3N/(5kg)(0.6) =10rad/sec^2

Also, if the question had said "hollow sphere" would the moment of inertia be different..(2/3)mr^2 ?

For a solid sphere, I ≠ mR2; I = (2/5) M ⋅ R2

Here is a list of the mass moments of inertia for a variety of different shapes:

https://en.wikipedia.org/wiki/List_of_moments_of_inertia
 
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