Rotational Mechanics -- A solid sphere is rolled on a rough surface

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SUMMARY

The discussion centers on the rotational mechanics of a uniform solid sphere rolling on a rough surface. The critical time when rotation ceases is established as 4v0 / (5μg), where μ represents the coefficient of friction. Participants derived the angular acceleration (α) using the equation T = Iα, resulting in α = 5μg / (2R). The conversation also explores the relationship between linear and angular velocities during the transition from skidding to rolling.

PREREQUISITES
  • Understanding of rotational dynamics and torque equations
  • Familiarity with the concepts of angular acceleration and linear velocity
  • Knowledge of friction coefficients and their effects on motion
  • Basic grasp of angular momentum conservation principles
NEXT STEPS
  • Explore the derivation of angular acceleration in different shapes, such as cylinders and disks
  • Learn about the effects of varying coefficients of friction on rolling motion
  • Investigate the relationship between linear and angular velocities in different rolling scenarios
  • Study the principles of energy conservation in rotational motion
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Physics students, mechanical engineers, and anyone interested in understanding the dynamics of rolling motion and rotational mechanics.

Ayesha02
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Homework Statement
A uniform solid sphere of mass M radius R is placed on a rough surface of given an initial linear velocity ##v_0## and angular velocity ##w_0##, where ##w_0## = ##v_0## /2R. plot the graph of angular speed about the center v/s time t.
Relevant Equations
##T## = I* alpha , where T= torque, alpha= angular acceleration
and
##w_0(f)## = ##w_0(i)##- alpha*t
I found out the time when rotation ceases to be 4 ##v_0## /5*mew*g, where mew=coefficient of friction of surface but I am unable to plot the graph post that time
 
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Ayesha02 said:
Homework Statement:: A uniform solid sphere of mass M radius R is placed on a rough surface of given an initial linear velocity ##v_0## and angular velocity ##w_0##, where ##w_0## = ##v_0## /2R. plot the graph of angular speed about the center v/s time t.
Relevant Equations:: ##T## = I* alpha , where T= torque, alpha= angular acceleration
and
##w_0(f)## = ##w_0(i)##- alpha*t

I found out the time when rotation ceases to be 4 ##v_0## /5*mew*g, where mew=coefficient of friction of surface but I am unable to plot the graph post that time
Is the initial angular velocity lower or greater than the one when the sphere rolls? The friction decreases linear velocity and either increases or decreases angular velocity, till rolling occurs. Determine both as functions of time, Show your work in detail.
 
Last edited:
ehild said:
The friction decreases linear velocity and increases angular velocity. Determine both as functions of time, Show your work in detail.

I just did
##T## = 2/5 M R^2 * α
which gives α =5μg/ 2R

hence
##w_0(f)## = ##w_0(i)## - α t
i.e 0= ##v_0##/2R - 5μg/ 2R *t

hence i got t=4##v_0##/5μg (time when rotation ceases)
 
Ayesha02 said:
I just did
##T## = 2/5 M R^2 * α
which gives α =5μg/ 2R

hence
##w_0(f)## = ##w_0(i)## - α t
i.e 0= ##v_0##/2R - 5μg/ 2R *t

hence i got t=4##v_0##/5μg (time when rotation ceases)
You kick a ball. After a short time, does it skid or does it roll?
 
ehild said:
You kick a ball. After a short time, does it skid or does it roll?

Skid initially, after some time rolls.
Im assuming the surface is rough
 
Ayesha02 said:
Skid initially, after some time rolls.
Im assuming the surface is rough
Yes. And what is the angular speed in case of pure rolling with respect to the linear velocity of the CM?
 
Last edited:
ehild said:
Yes. And what is the angular speed in case of pure rolling with respect to the linear velocity of the CM?

Angular momentum conservation

I got the answer:bow:
 

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